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Kaya Rengest

04/09/2017 at 14:53
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\(\dfrac{1}{2}\) + \(\dfrac{1}{6}\) + ...+ \(\dfrac{1}{30}\)  + \(\dfrac{1}{42}\)=?




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    Math You Like 04/09/2017 at 15:00

    \(\dfrac{1}{2}\) + \(\dfrac{1}{6}\) + ... + \(\dfrac{1}{30}\) + \(\dfrac{1}{42}\)

    =\(\dfrac{1}{1.2}\) + \(\dfrac{1}{2.3}\) + ... + \(\dfrac{1}{5.6}\) + \(\dfrac{1}{6.7}\)

    =\(\dfrac{1}{1}\) - \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\) + ... + \(\dfrac{1}{5}\) - \(\dfrac{1}{6}\) + \(\dfrac{1}{6}\) - \(\dfrac{1}{7}\)

    =\(\dfrac{1}{1}\) - \(\dfrac{1}{7}\)

    =\(\dfrac{6}{7}\)

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    Kaya Rengest 04/09/2017 at 15:14

    Thank you. You are very good


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