Phan Thanh Tinh Coordinator
04/09/2017 at 11:57-
Dao Trong Luan 04/09/2017 at 13:14
Suppose \(\dfrac{x}{x-4}\Rightarrow a=\dfrac{x}{\overline{x-4|x}}\)
a,
a = \(-\dfrac{3}{13}=\dfrac{-3}{13}=\dfrac{3}{-13}\)
\(\Rightarrow\left[{}\begin{matrix}x-4=1\\x-4=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=3\end{matrix}\right.\)
Easy see x = 3 => a \(=-\dfrac{3}{13}\)
So x = 3
b,
a = 1/6
=> a - 4 \(\ge0\)
=> a > 4
\(\Rightarrow5\le x\le9\)
\(\Rightarrow1\le x-4\le5\)
\(\Rightarrow a\in\left\{\dfrac{5}{15};\dfrac{6}{26};\dfrac{7}{37};\dfrac{8}{48};\dfrac{9}{59}\right\}\)
Have 8/48 = 1/6
So a = 8/48
=> x = 8
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Dao Trong Luan's solution isn't logical at all. I need another one.