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Dao Trong Luan 03/09/2017 at 19:30
a \(⋮4\)
=> a \(⋮\)divisor of 4
=> a \(⋮\pm1;\pm2;\pm4\)
So a \(⋮4\Rightarrow a⋮\pm1;\pm2;\pm4\)
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a \(⋮4\)
=> a \(⋮\)divisor of 4
=> a \(⋮\pm1;\pm2;\pm4\)
So a \(⋮4\Rightarrow a⋮\pm1;\pm2;\pm4\)