t's incomplete :)

We easily have 2 equations :

{5k−4m=7⇒4(5k−4m)=20k−16m=285m+4k=22⇒5(5m+4k)=25m+20k=110

⇔25m+20k−(20k−16m)=110−28

⇔41m=82

⇔m=2

⇔k=3

Therefore, ...

It's incomplete :)

We easily have 2 equations :

\(\left\{{}\begin{matrix}5k-4m=7\Rightarrow4\left(5k-4m\right)=20k-16m=28\\5m+4k=22\Rightarrow5\left(5m+4k\right)=25m+20k=110\end{matrix}\right.\)

\(\Leftrightarrow25m+20k-\left(20k-16m\right)=110-28\)

\(\Leftrightarrow41m=82\)

\(\Leftrightarrow m=2\)

\(\Leftrightarrow k=3\)

Therefore, ...