{3x−2y−8=02x+3y=1⇒{6x−4y=166x+9y=3

⇒⎧⎨⎩13y=−13x=1−3y2⇒{x=2y=−1

Replace x = 2 and y = -1 into x = ky + 4,we have :

2 = -k + 4 => -k = -2 => k = 2

\(\left\{{}\begin{matrix}3x-2y-8=0\\2x+3y=1\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}6x-4y=16\\6x+9y=3\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}13y=-13\\x=\dfrac{1-3y}{2}\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=2\\y=-1\end{matrix}\right.\)

Replace x = 2 and y = -1 into x = ky + 4,we have :

2 = -k + 4 => -k = -2 => k = 2