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VTK-VangTrangKhuyet 21/08/2017 at 14:24
We have : \(AH^2=BH\cdot CH\Leftrightarrow3^2=BH\cdot6\Rightarrow BH=\dfrac{9}{6}=\dfrac{3}{2}\)
So \(BC=BH+CH=6+\dfrac{3}{2}=7,5\)
=> \(AC^2=7,5\cdot6\Rightarrow AC=3\sqrt{5}\)
So the area of the triangle ABC is
\(S_{ABC}=\dfrac{1}{2}\cdot AB\cdot AC=\dfrac{1}{2}\cdot5\cdot3\sqrt{5}=\dfrac{15\sqrt{5}}{2}\)
Selected by MathYouLike -
Luffy xyz 123 21/08/2017 at 14:19
The area of the triagle ABC is:
( 5 x 3 ) : 2 = 7,5 ( ....2 )
Answer: 7,5 ....2
Where is the unit Summer Clouds ?