C, 239 nha

Let a,b,c,d,e be the weights of 5 boys respectively. We have :

\(\left(a+b\right)+\left(a+c\right)+\left(a+d\right)+\left(a+e\right)+\left(b+c\right)+\left(b+d\right)+\left(b+e\right)+\left(c+d\right)+\left(c+e\right)+\left(d+e\right)\)

\(=90+92+93+94+95+96+97+98+100+101\)

\(\Leftrightarrow4\left(a+b+c+d+e\right)=956\)\(\Rightarrow a+b+c+d+e=239\)

So, the total weight of 5 boys is 239 kg (C)