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20/08/2017 at 16:59-
Luffy xyz 123 20/08/2017 at 17:01A = \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+........+\dfrac{1}{34.35}\)
A = 1 - \(\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+..........+\dfrac{1}{34}-\dfrac{1}{35}\)
=> A = 1 - \(\dfrac{1}{35}\)= \(\dfrac{35}{35}-\dfrac{1}{35}=\dfrac{34}{5}\)
So, A = \(\dfrac{34}{5}\)
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