You are wrong ! @Kaya Renger 

Use Zigma to calculator the sum A , we have :

\(\sum\limits^{105}_{x=0}\left(1+X\right)=5670\)

So A = 5670 

1 = 1 + 0

2 = 1 + 1

4 = 2 + 2

7 = 4 + 3

Next numbers are:

7 + 4 = 11

11 + 5 = 16

16 + 6 = 22

22 + 7 = 29

29 + 8 = 37

37 + 9 = 46

46 + 10 = 56

56 + 11 = 67

67 + 12 = 79

79 + 13 = 92

And the last is 106 = 92 + 16

So A or their sum are:

1 + 2 + 4 + 7 + 11 + 16 + 22 + 29 + 37 + 46 + 56 + 67 + 79 + 92 + 106 = 508

OK???