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Hương Yêu Dấu

19/08/2017 at 16:23
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4
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\(\dfrac{1}{2}\)+\(\dfrac{2}{3}\)+\(\dfrac{3}{4}\)+\(\dfrac{1}{3}\)=?




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  • ...
    Help you solve math 19/08/2017 at 16:29

       \(\dfrac{1}{2}\)+\(\dfrac{2}{3}\)+\(\dfrac{3}{4}\)+\(\dfrac{1}{3}\)

    =\(\dfrac{7}{6}\)+\(\dfrac{3}{4}\)+\(\dfrac{1}{3}\)

    =\(\dfrac{23}{12}\)+\(\dfrac{1}{3}\)

    =\(\dfrac{9}{4}\)

    Hương Yêu Dấu selected this answer.
  • ...
    Dao Trong Luan 19/08/2017 at 17:51

    \(\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4}+\dfrac{1}{3}\)

    \(=\left(\dfrac{2}{4}+\dfrac{3}{4}\right)+\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\)

    \(=\dfrac{5}{4}+1=\dfrac{5}{4}+\dfrac{4}{4}=\dfrac{9}{4}\)

    My answer is faster than Help you solve math's answer.
    *---*GOOD LUCK*---*

  • ...
    nguyển văn hải 20/08/2017 at 08:26

    \(\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4}+\dfrac{1}{3}\)

    \(=\left(\dfrac{2}{4}+\dfrac{3}{4}\right)+\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\)

    \(=\dfrac{5}{4}+1\)

    \(=\dfrac{9}{4}\)

  • ...
    Ngân Hà 19/08/2017 at 20:24

    \(\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4}+\dfrac{1}{3}\)

    \(=\left(\dfrac{1}{2}+\dfrac{3}{4}\right)+\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\)

    \(=\left(\dfrac{2}{4}+\dfrac{3}{4}\right)+1\)

    \(=\dfrac{5}{4}+1\)

    \(=\dfrac{9}{4}\)

    Dao Trong Luan's answer is faster than mine, he's doing just right. ;)


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