Hương Yêu Dấu
19/08/2017 at 16:23-
Help you solve math 19/08/2017 at 16:29
\(\dfrac{1}{2}\)+\(\dfrac{2}{3}\)+\(\dfrac{3}{4}\)+\(\dfrac{1}{3}\)
=\(\dfrac{7}{6}\)+\(\dfrac{3}{4}\)+\(\dfrac{1}{3}\)
=\(\dfrac{23}{12}\)+\(\dfrac{1}{3}\)
=\(\dfrac{9}{4}\)
Hương Yêu Dấu selected this answer. -
Dao Trong Luan 19/08/2017 at 17:51
\(\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4}+\dfrac{1}{3}\)
\(=\left(\dfrac{2}{4}+\dfrac{3}{4}\right)+\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\)
\(=\dfrac{5}{4}+1=\dfrac{5}{4}+\dfrac{4}{4}=\dfrac{9}{4}\)
My answer is faster than Help you solve math's answer.
*---*GOOD LUCK*---* -
nguyển văn hải 20/08/2017 at 08:26
\(\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4}+\dfrac{1}{3}\)
\(=\left(\dfrac{2}{4}+\dfrac{3}{4}\right)+\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\)
\(=\dfrac{5}{4}+1\)
\(=\dfrac{9}{4}\)
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Ngân Hà 19/08/2017 at 20:24
\(\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4}+\dfrac{1}{3}\)
\(=\left(\dfrac{1}{2}+\dfrac{3}{4}\right)+\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\)
\(=\left(\dfrac{2}{4}+\dfrac{3}{4}\right)+1\)
\(=\dfrac{5}{4}+1\)
\(=\dfrac{9}{4}\)
Dao Trong Luan's answer is faster than mine, he's doing just right. ;)