steve jobs
17/03/2017 at 14:12-
Trần Quang Linh 17/03/2017 at 15:59
A=\(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\)
128A=64+32+16+8+4+2+1
128A=127
A=\(\dfrac{127}{128}\)
steve jobs selected this answer. -
Love people Name Jiang 17/03/2017 at 18:43
For : \(A=\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\)
\(\Rightarrow2A=1+\dfrac{1}{2}+\dfrac{1}{4}+.....+\dfrac{1}{128}\)
\(\Rightarrow2A-A=1-\dfrac{1}{128}\)
\(\Rightarrow A=\dfrac{127}{128}\)
-
FA KAKALOTS 03/02/2018 at 12:46
For : A=12+14+18+132+164+1128
⇒2A=1+12+14+.....+1128
⇒2A−A=1−1128
⇒A=127128