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Lê Quốc Trần Anh Coordinator

15/08/2017 at 09:47
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For how many nonzero values of x does x\(^{2x}\) = 1?




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  • ...
    Kaya Renger Coordinator 15/08/2017 at 10:21

    With x2x = 1

    \(\Rightarrow\left[{}\begin{matrix}x=1\\2x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=0\end{matrix}\right.\)

    But the question asked how many non-zero values of x 

    So that : x = 1 

  • ...
    Phan Thanh Tinh Coordinator 15/08/2017 at 14:10

    \(x^{2x}=1\Leftrightarrow\left(x^x\right)^2=1\Rightarrow\left[{}\begin{matrix}x^x=1\\x^x=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)

    P/S : Kaya Renger missed a root.


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