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Summer Clouds moderators

15/08/2017 at 09:06
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A triangle has a base of 3 feet and a height of 6 feet. If its area is increased to 35 \(ft^2\) by increasing the base and height by the same number of feet, what is the sum of the new base and height?




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    Phan Thanh Tinh Coordinator 15/08/2017 at 09:52

    The base and height both increase by x feet \(\left(x>0\right)\).We have :

    \(\dfrac{\left(x+3\right)\left(x+6\right)}{2}=35\)\(\Leftrightarrow x^2+9x+18=70\)

    \(\Leftrightarrow x^2+9x-52=0\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{-9+\sqrt{81+4.52}}{2}=4\\x=\dfrac{-9-\sqrt{81-4.52}}{2}=-13\end{matrix}\right.\)

    Since x > 0, x = 4 and x + 3 = 7 ; x + 6 = 10

    Hence,the answer is : 7 + 10 = 17 (feet)

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