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\(1\sqrt{4}+1\sqrt{4}+\sqrt[1]{5+\dfrac{5}{6}}=2+2+5+\dfrac{5}{6}=9\dfrac{5}{6}=\dfrac{59}{6}\)
P/S : Dao Trong Luan was wrong
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Dao Trong Luan 13/08/2017 at 10:43
\(1\sqrt{4}+1\sqrt{4}+\sqrt[1]{5+\dfrac{5}{6}}\)
\(=1\cdot2+1\cdot2+\sqrt{5+\dfrac{5}{6}}\)
\(=2+2+\sqrt{\dfrac{210}{6}}\)
\(=4+\sqrt{\dfrac{210}{6}}\)
\(=\dfrac{24}{6}+\dfrac{\sqrt{210}}{6}=\dfrac{24+\sqrt{210}}{6}\)