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Phan Thanh Tinh Coordinator

12/08/2017 at 10:05
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Given \(\Delta ABC\) with point M inside so that SAMB + SBMC = SMAC

Prove that M moves on the midsegment of \(\Delta ABC\) which is parallel to AC




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    Đức Lê Minh 15/08/2017 at 20:01

    M moves on average line of \(\Delta ABC\) which is matched from the midpoint of AB to the midpoint of BC


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