Kayasari Ryuunosuke Coordinator
07/08/2017 at 14:41-
AL 07/08/2017 at 17:02Use AM-GM's inequality we have:
\(\dfrac{abc}{\left(a+b\right)\left(b+c\right)\left(c+a\right)}\le\dfrac{abc}{2\sqrt{ab}\cdot2\sqrt{bc}\cdot2\sqrt{ca}}\)\(=\dfrac{abc}{8abc}=\dfrac{1}{8}\)
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Phan Huy Toàn 12/08/2017 at 15:07AL very good