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Trường Sơn Nguyễn

07/08/2017 at 13:08
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Bài 1 : Tìm số dư : 2^1 + 3^5 + 4^9 + … + 2003^8005 chia cho 5 
Bài 2 : Tìm chữ số tận cùng của: 2^2 + 3^6 + 4^10 + … + 2004^8010




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    Lê Quốc Trần Anh Coordinator 07/08/2017 at 13:15

    2: Every exponential in the equation that the index number :4 have the remainder 1. So that every exponential in the equation has the same ending number, equals to:

    \(\left(2+3+4+...+9\right)+199.\left(1+2+...+9\right)+1+2+3+4=9009.\)

    So the last number of it is: 9

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    Lê Quốc Trần Anh Coordinator 07/08/2017 at 13:19

    P/s: Vietnamese is permitted in Mathu.

    Source: https://sites.google.com/site/toanhoctoantap/chuyen-dhe-toan-hoc/tim-chu


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