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Behind You

07/08/2017 at 11:57
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Solve :

\(x^2+3x+1=\left(x+3\right)\sqrt{x^2+1}\)




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    WhySoSerious 07/08/2017 at 12:03

    The expression is determined with all \(x\in R\)

    \(\Leftrightarrow x^2+1+3x-x\sqrt{x^2+1}-3\sqrt{x^2+1}=0\)

    \(\Leftrightarrow\left(x^2+1\right)^2-x\sqrt{x^2+1}+3x-3\sqrt{x^2+1}=0\)

    \(\Leftrightarrow\sqrt{x^2+1}\left(\sqrt{x^2+1}-x\right)-3\left(\sqrt{x^2+1}-x\right)=0\)

    \(\Leftrightarrow\left(\sqrt{x^2+1}-x\right)\left(\sqrt{x^2+1}-3\right)=0\)

    \(\Rightarrow\left[{}\begin{matrix}\sqrt{x^2+1}=x\left(not-satisfy\right)\\\sqrt{x^2+1}=3\end{matrix}\right.\Leftrightarrow x=\pm2\sqrt{2}\)

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