Phan Thanh Tinh Coordinator
02/08/2017 at 20:40-
یևσϞջ♱ɮևσϞ➪ȿ₂ 03/08/2017 at 09:47We have \(\dfrac{23}{7}=3+\dfrac{2}{7}=3+\dfrac{1}{\dfrac{7}{2}}=3+\dfrac{1}{3+\dfrac{1}{2}}=3+\dfrac{1}{3+\dfrac{1}{1+1}}\)
So (a;b;c)=(3;3;1).
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baohong912006 04/08/2017 at 08:46
We have 237=3+27=3+172=3+13+12=3+13+11+1237=3+27=3+172=3+13+12=3+13+11+1
So (a;b;c)=(3;3;1).
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You must explain why the values you found are the only