It's a good problem :((

So we have the time is \(\dfrac{2}{60}\left(hour\right)=\dfrac{1}{30}\)

So we have the speed to get to each intersection right on the first time is : \(\dfrac{3,5}{x}=\dfrac{1}{30}\Rightarrow x=105\) (kilometres per hour).

So he can travel to get to each intersection at the third time as it just changes to green at the speed of \(\dfrac{105}{3}=35\) (kilometres per hour)

That's what I think :))

It's a good problem :((

So we have the time is 260(hour)=130

So we have the speed to get to each intersection right on the first time is : 3,5x=130⇒x=105

 (kilometres per hour).

So he can travel to get to each intersection at the third time as it just changes to green at the speed of 1053=35

 (kilometres per hour)

That's what I think :))