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Aim Egst 25/07/2017 at 21:57
1,\(x\left(x-3\right)+x-3=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-3\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+1=0\\x-3=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=3\end{matrix}\right.\)
2,\(5x\left(x-2\right)-x+2=0\)
\(\Leftrightarrow5x\left(x-2\right)-\left(x-2\right)=0\)
\(\Leftrightarrow\left(5x-1\right)\left(x-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}5x-1=0\\x-2=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=2\end{matrix}\right.\)
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Hiệp Dương 26/07/2017 at 11:01
1,x(x − 3) + x − 3 = 0
=> (x - 3)(x + 1) = 0
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)