MathYouLike MathYouLike
  • Toggle menubar
  • Toggle fullscreen
  • Toggle Search
  •    Sign up
  • QUESTIONS
  • TAGS
  • USERS
  • BADGES
  • UNANSWERD
  • ASK A QUESTION
  • BLOG
...

ღ kekio ღ

25/07/2017 at 21:51
Answers
2
Follow

Search x know

1,\(x\left(x-3\right)+x-3=0\)

2,\(5x\left(x-2\right)-x+2=0\)




    List of answers
  • ...
    Aim Egst 25/07/2017 at 21:57

    1,\(x\left(x-3\right)+x-3=0\)

    \(\Leftrightarrow\left(x+1\right)\left(x-3\right)=0\)

    \(\Rightarrow\left[{}\begin{matrix}x+1=0\\x-3=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=3\end{matrix}\right.\)

    2,\(5x\left(x-2\right)-x+2=0\)

    \(\Leftrightarrow5x\left(x-2\right)-\left(x-2\right)=0\)

    \(\Leftrightarrow\left(5x-1\right)\left(x-2\right)=0\)

    \(\Rightarrow\left[{}\begin{matrix}5x-1=0\\x-2=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=2\end{matrix}\right.\)

    Selected by MathYouLike
  • ...
    Hiệp Dương 26/07/2017 at 11:01

    1,x(x − 3) + x − 3 = 0

    => (x - 3)(x + 1) = 0

    \(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+1=0\end{matrix}\right.\)

    ​\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)


Post your answer

Please help ღ kekio ღ to solve this problem!



Weekly ranking


© HCEM 10.1.29.225
Crafted with by HCEM