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Lê Quốc Trần Anh Coordinator

17/07/2017 at 12:04
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What is the smallest common denominator of:

\(\dfrac{2^{10}.9^6}{4^6.3^{11}}\) ; \(\dfrac{6^{12}}{9^5.2^{14}}\) and \(\dfrac{15^5.2^6.3^3}{5^6.6^8}\)




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    Phan Thanh Tinh Coordinator 17/07/2017 at 12:45

    We must reduce the fractions :

    \(\dfrac{2^{10}.9^6}{4^6.3^{11}}=\dfrac{2^{10}.\left(3^2\right)^6}{\left(2^2\right)^6.3^{11}}=\dfrac{2^{10}.3^{12}}{2^{12}.3^{11}}=\dfrac{3}{2^2}\)

    \(\dfrac{6^{12}}{9^5.2^{14}}=\dfrac{\left(2.3\right)^{12}}{\left(3^2\right)^5.2^{14}}=\dfrac{2^{12}.3^{12}}{3^{10}.2^{14}}=\dfrac{3^2}{2^2}\)

    \(\dfrac{15^5.2^6.3^3}{5^6.6^8}=\dfrac{\left(3.5\right)^5.2^6.3^3}{5^6.\left(2.3\right)^8}=\dfrac{3^8.2^6.5^5}{3^8.2^8.5^6}=\dfrac{1}{2^2.5}\)

    The smallest common denominator of 3 fractions is 22.5 = 20

    Lê Quốc Trần Anh selected this answer.

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