Summer Clouds moderators
16/07/2017 at 11:48-
\(A=\dfrac{\left(2^2\right)^{20}.\left(3^2\right)^{25}.\left(5^2\right)^4.\left(3^2\right)}{4^{21}.9^{25}.3^2.5^8}\)
\(A=\dfrac{4^{20}.9^{25}.5^8.3^2}{4^{21}.9^{25}.3^2.5^8}\)
\(A=\dfrac{1.1.1.1}{4.1.1.1}\)
\(A=\dfrac{1}{4}\)
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FA KAKALOTS 08/02/2018 at 22:00A=(22)20.(32)25.(52)4.(32)421.925.32.58
A=420.925.58.32421.925.32.58
A=1.1.1.14.1.1.1
A=14
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nhathuyth1 03/05/2018 at 12:56\(A=\dfrac{2^{40}.3^{50}.25^4.9}{4^{21}.9^{25}.3^2.5^8}\)
\(A=\dfrac{2^{40}.3^{50}.\left(5^2\right)^4.3^2}{\left(2^2\right)^{21}.\left(3^2\right)^{25}.3^2.5^8}\)
\(A=\dfrac{2^{40}.3^{50}.5^8.3^2}{2^{42}.3^{50}.3^2.5^8}\)
\(A=\dfrac{1}{2^2}=\dfrac{1}{4}\)