Phan Thanh Tinh Coordinator
15/07/2017 at 23:39-
Given a + b + c = 3.Simply the fraction :\(\dfrac{a^3+b^3+c^3-3abc}{\left(a-b\right)^3+\left(b-c\right)^3+\left(c-a\right)^3}\)
Given a + b + c = 3.Simply the fraction :\(\dfrac{a^3+b^3+c^3-3abc}{\left(a-b\right)^3+\left(b-c\right)^3+\left(c-a\right)^3}\)