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Summer Clouds moderators

15/07/2017 at 15:56
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Consider fractions equivalent to \(\dfrac{2}{3};\dfrac{4}{6};\dfrac{6}{9};\dfrac{8}{12};\dfrac{10}{15};....\)




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    Kayasari Ryuunosuke Coordinator 15/07/2017 at 17:14

    We have : 

    \(\dfrac{2}{3}=\dfrac{2.1}{3.1}\)

    \(\dfrac{4}{6}=\dfrac{2.2}{3.2}=\dfrac{2}{3}\)

    \(\dfrac{6}{9}=\dfrac{2.3}{3.3}=\dfrac{2}{3}\)

    ..........

    From the above analysis, we derive the general formula , is :

    \(\dfrac{2}{3}=\dfrac{4}{6}=\dfrac{6}{9}=\dfrac{8}{12}=\dfrac{10}{15}=...........=\dfrac{2.k}{3.k}\) (with k > 0)

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