Summer Clouds moderators
15/07/2017 at 15:56-
We have :
\(\dfrac{2}{3}=\dfrac{2.1}{3.1}\)
\(\dfrac{4}{6}=\dfrac{2.2}{3.2}=\dfrac{2}{3}\)
\(\dfrac{6}{9}=\dfrac{2.3}{3.3}=\dfrac{2}{3}\)
..........
From the above analysis, we derive the general formula , is :
\(\dfrac{2}{3}=\dfrac{4}{6}=\dfrac{6}{9}=\dfrac{8}{12}=\dfrac{10}{15}=...........=\dfrac{2.k}{3.k}\) (with k > 0)
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