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Lê Quốc Trần Anh Coordinator

12/07/2017 at 09:26
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Compact:

\(\dfrac{2^2.3^2.4^2.5^2}{28800}\)




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    Kayasari Ryuunosuke Coordinator 12/07/2017 at 09:28

    \(\dfrac{2^2.3^2.4^2.5^2}{28800}=\dfrac{\left(2.3.4.5\right)^2}{28800}=\dfrac{120^2}{2.14400}=\dfrac{120^2}{2.120^2}=\dfrac{1}{2}\)

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