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Lê Quốc Trần Anh Coordinator

12/07/2017 at 09:16
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2
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We have:

\(P=\dfrac{4n+1}{2n+3}\) . Find \(n\) so that \(P\) is a natural number.




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  • ...
    Phan Thanh Tinh Coordinator 12/07/2017 at 09:46

    Kayasari Ryuunosuke.you should write \(2n+3\in D\left(5\right)\)

    Lê Quốc Trần Anh selected this answer.
  • ...
    Kayasari Ryuunosuke Coordinator 12/07/2017 at 09:22

    P is a natural number 

    <=> 4n + 1 \(⋮\) 2n + 3

    <=> 4n + 6 - 6 + 1 \(⋮\) 2n + 3

    <=> 2(2n + 3) - 5 \(⋮\) 2n + 3

    <=> 5 \(⋮\) 2n + 3

    => 2n + 3 \(\inƯ\left(5\right)=\left\{1;-1;5;-5\right\}\)

    We have a table :

    2n + 3       1                  -1                 5            -5    
    n -1 -2 1 4

    Hence , n = {-1 ; -2 ; 1 ; 4}

    \(⋮\) 


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