Lê Quốc Trần Anh Coordinator
11/07/2017 at 13:35-
Bui Duy Vuong 11/07/2017 at 14:39Condition determines: \(14x-42\ne0\Leftrightarrow x\ne3\).
Lê Quốc Trần Anh selected this answer.
We have:
\(\dfrac{7\left(x-3\right)}{14\left(x-3\right)}=\dfrac{7}{14}=\dfrac{7:7\times2}{14:7\times2}=\dfrac{2}{4}\) -
FA KAKALOTS 28/01/2018 at 22:14Condition determines: 14x−42≠0⇔x≠3.
We have:
7(x−3)14(x−3)=714=7:7×214:7×2=24