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Lê Quốc Trần Anh Coordinator

11/07/2017 at 09:44
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Prove that:

\(\dfrac{12n+1}{30n+2}:d\) \(\left(d=1\right)\)




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    Phan Thanh Tinh Coordinator 11/07/2017 at 10:34

    Let d be the common divisor of 12n + 1 and 30n + 2.We have :

    \(12n+1⋮d\Rightarrow5\left(12n+1\right)⋮d\Rightarrow60n+5⋮d\)

    \(30n+2⋮d\Rightarrow2\left(30n+2\right)⋮d\Rightarrow60n+4⋮d\)

    \(\Rightarrow\left(60n+5\right)-\left(60n+4\right)⋮d\Rightarrow1⋮d\Rightarrow d=\pm1\)

    So \(\dfrac{12n+1}{30n+2}\) is a fraction in lowest terms with any \(n\in Z\)

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