Lê Quốc Trần Anh Coordinator
11/07/2017 at 09:40-
Dao Trong Luan 24/07/2017 at 10:22
\(\dfrac{9}{10\text{!}}+\dfrac{9}{11\text{!}}+...+\dfrac{9}{1000\text{!}}=\dfrac{10-1}{10\text{!}}+\dfrac{10-1}{11\text{!}}+...+\dfrac{10-1}{1000\text{!}}\)
\(=\dfrac{10}{10\text{!}}-\dfrac{1}{10\text{!}}+\dfrac{10}{11\text{!}}-\dfrac{1}{11\text{!}}+...+\dfrac{10}{1000\text{!}}-\dfrac{1}{1000\text{!}}\)
\(=\dfrac{1}{9\text{!}}-\dfrac{1}{10\text{!}}+\dfrac{1}{10\text{!}}-\dfrac{1}{11\text{!}}+...+\dfrac{1}{999\text{!}}-\dfrac{1}{1000\text{!}}\)
\(=\dfrac{1}{9\text{!}}-\dfrac{1}{1000\text{!}}< \dfrac{1}{9\text{!}}\)
=> \(\dfrac{9}{10\text{!}}+\dfrac{9}{11\text{!}}+...+\dfrac{9}{1000\text{!}}< \dfrac{1}{9\text{!}}\)
True or False???
Lê Quốc Trần Anh selected this answer. -
FA KAKALOTS 28/01/2018 at 22:15
910!+911!+...+91000!=10−110!+10−111!+...+10−11000!
=1010!−110!+1011!−111!+...+101000!−11000!
=19!−110!+110!−111!+...+1999!−11000!
=19!−11000!<19!
=> 910!+911!+...+91000!<19!
True or False??? [haha]