Call the time Peter was running is y, the time Peter was not running is x.
If call Jane's speed is a then Peter's speed is 4a.
Jane was running is x + y(time units) so a(x+y) = 5000 (m).
Peter was running is y (time units) so 4a.y = 4900(m)
We have:   \(\dfrac{a\left(x+y\right)}{4a.y}=\dfrac{5000}{4900}=\dfrac{50}{49}\)
Then: \(49.\left(x+y\right)=200y\)\(\Leftrightarrow49x=151y\)\(\Leftrightarrow\dfrac{x}{151}=\dfrac{y}{49}\)

Calling the distance that Jane was run dring the time was not running is X(m) and call the distance that Jane was run dring the time running is Y(m).
Because the distance is proportional to the time of coal so:
\(\dfrac{X}{151}=\dfrac{Y}{49}=\dfrac{X+Y}{151+49}=\dfrac{5000}{200}=25\)
Then  \(X=151.25=3775\left(m\right)\).