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Summer Clouds moderators

27/06/2017 at 08:59
Answers
4
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Find x, y satisfy \(\dfrac{x}{2}=\dfrac{y}{3}\) and \(x+y=12\).




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    Phan Thanh Tinh Coordinator 27/06/2017 at 11:57

    By applying the property of sequence of equivalent ratios,we have :

    \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{x+y}{2+3}=\dfrac{12}{5}=2.4\)\(\Rightarrow\left\{{}\begin{matrix}x=2.4\times2=4.8\\y=2.4\times3=7.2\end{matrix}\right.\)

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    I like Math English 07/10/2017 at 17:17

    I play soccer and play games

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    Math You Like 07/10/2017 at 17:15

    Very good

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    Lê Quốc Trần Anh Coordinator 27/06/2017 at 09:22

    Arrcoding to the context, \(\dfrac{x}{2}=\dfrac{y}{3}\)

    =>\(x.3=y.2\)   => \(\dfrac{3}{2}x=y\)  => \(x< y\)

    We have 5 cases that satisfy\(x< y\)   and \(x+y=12\) . They are: 1+11 ; 2+10 ; 3+9 ; 4+8 ; 5+7. (We avoid\(-x\) and \(y\)   because \(-x\ne y\) ) In that 5 cases, no case are suitable for this text => NO ANSWER.

    Answer: NO ANSWER


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