\(A=\dfrac{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{9}}{\dfrac{4}{3}+\dfrac{4}{5}-\dfrac{4}{9}}=\dfrac{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{9}}{2\left(\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{9}\right)}=\dfrac{1}{2}=0.5\)