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Condition : \(3x+1\ne0\Leftrightarrow x\ne-\dfrac{1}{3}\)
\(\dfrac{x-1}{3x+1}=\dfrac{1}{2}\Leftrightarrow2\left(x-1\right)=3x+1\Leftrightarrow3x+1-2x+2=0\)
\(\Leftrightarrow x+3=0\Leftrightarrow x=-3\)
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Thu Thảo 17/06/2017 at 22:02Condittion: \(3x+1\ne0\)
\(\Rightarrow x\ne-\dfrac{1}{3}\)
\(\dfrac{x-1}{3x+1}=\dfrac{1}{2}\)
\(\Rightarrow2\left(x-1\right)=3x+1\)
\(\Leftrightarrow2x-2=3x+1\)
\(\Leftrightarrow2x-3x=1+2\)
\(\Leftrightarrow-x=3\)
\(\Leftrightarrow x=-3\) (satisfy)