There is something to ask
11/03/2017 at 20:35-
Love the Name of Jiang 11/03/2017 at 20:39We have \(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{a}=\dfrac{a+b+c}{b+c+a}=1\)
Then : \(\dfrac{a}{b}=1\Rightarrow a=b\)
\(\dfrac{b}{c}=1\Rightarrow b=c\)
\(\dfrac{c}{a}=1\Rightarrow c=a\)
Deduced : a = b = c
Which top post for a + b + c = 2007 => 3a = 2007 => a = 2007 : 3 = 669
Dress a = b = c = 669
There is something to ask good because neck one question or
There is something to ask selected this answer. -
Love the Name of Jiang 11/03/2017 at 20:53
Can not believe someone z
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Love the Name of Jiang 11/03/2017 at 20:46
No Kurosaki Akatsu I do not do not copy your articles do not shamelessly z look back . You Is answering that wrong
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There is something to ask 11/03/2017 at 20:43
I agree with Love's name of Jiang
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Love the Name of Jiang 11/03/2017 at 20:42
Kurosaki Akatsu and Love the Name of Jiang good
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Applying the same sequence properties, we have
\(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{a}=\dfrac{a+b+c}{b+c+a}=1\)
\(\Rightarrow\left\{{}\begin{matrix}a=b\\b=c\\c=a\end{matrix}\right.\Rightarrow a=b=c\)
Change a = b = c , i have :
a + b + c = a + a + a = 2017
=> 3a = 2017
=> \(a=\dfrac{2017}{3}\)
=> \(a=b=c=\dfrac{2017}{3}\)
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35 Tiểu Bảo 03/04/2017 at 21:16Give : x−12=y+34=z−56=kx−12=y+34=z−56=k
⇒⎧⎪⎨⎪⎩x=2k+1y=4k−3z=6k+5⇒{x=2k+1y=4k−3z=6k+5
Change x,y,z into 5z - 3x - 4y = 50 , we have :
5(6k + 5) - 3(2k + 1) - 4(4k - 3) = 50
30k + 25 - 6k - 3 - 16k + 12 = 50
8k + 34 = 50
8k = 16
=> k = 2
⇒⎧⎪⎨⎪⎩x=2k+1=2.2+1=5y=4k−3=4.2−3=5z=6k+5=6.2+5=17
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→இے๖ۣۜBoy™†hïếuGîa 23/03/2017 at 17:17We have ab=bc=ca=a+b+cb+c+a=1ab=bc=ca=a+b+cb+c+a=1
Then : ab=1⇒a=bab=1⇒a=b
bc=1⇒b=cbc=1⇒b=c
ca=1⇒c=aca=1⇒c=a
Deduced : a = b = c
Which top post for a + b + c = 2007 => 3a = 2007 => a = 2007 : 3 = 669
Dress a = b = c = 669
There is something to ask good because neck one question or
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Hoang Duc Hai 12/03/2017 at 19:23
We have ab=bc=ca=a+b+cb+c+a=1ab=bc=ca=a+b+cb+c+a=1
Then : ab=1⇒a=bab=1⇒a=b
bc=1⇒b=cbc=1⇒b=c
ca=1⇒c=aca=1⇒c=a
Deduced : a = b = c
Which top post for a + b + c = 2007 => 3a = 2007 => a = 2007 : 3 = 669
Dress a = b = c = 669
There is something to ask good because neck one question or
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Love the Name of Jiang 11/03/2017 at 20:53
You see you to you to your coppy
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you lost the very important rules , i don't want to talk to you anymore .
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Love the Name of Jiang 11/03/2017 at 20:51
Immerse yourself in the equality of the score
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If you say i am wrong about 2017 , i agree , but about you , from where do you have \(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{a}=\dfrac{a+b+c}{b+c+a}=1\)
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Love the Name of Jiang 11/03/2017 at 20:50
No 2017 yes 2007
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About what , show me !Love the Name of Jiang
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Love the Name of Jiang . Stop rewrite my anwser , you will be bad if you still do that !
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Love the Name of Jiang 11/03/2017 at 20:40
Kurosaki Akatsu good .